3.3.68 \(\int \frac {x^4}{(a+b x)^2 (c+d x)^2} \, dx\)

Optimal. Leaf size=124 \[ -\frac {a^4}{b^3 (a+b x) (b c-a d)^2}-\frac {2 a^3 (2 b c-a d) \log (a+b x)}{b^3 (b c-a d)^3}-\frac {c^4}{d^3 (c+d x) (b c-a d)^2}-\frac {2 c^3 (b c-2 a d) \log (c+d x)}{d^3 (b c-a d)^3}+\frac {x}{b^2 d^2} \]

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Rubi [A]  time = 0.13, antiderivative size = 124, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.056, Rules used = {88} \begin {gather*} -\frac {a^4}{b^3 (a+b x) (b c-a d)^2}-\frac {2 a^3 (2 b c-a d) \log (a+b x)}{b^3 (b c-a d)^3}-\frac {c^4}{d^3 (c+d x) (b c-a d)^2}-\frac {2 c^3 (b c-2 a d) \log (c+d x)}{d^3 (b c-a d)^3}+\frac {x}{b^2 d^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^4/((a + b*x)^2*(c + d*x)^2),x]

[Out]

x/(b^2*d^2) - a^4/(b^3*(b*c - a*d)^2*(a + b*x)) - c^4/(d^3*(b*c - a*d)^2*(c + d*x)) - (2*a^3*(2*b*c - a*d)*Log
[a + b*x])/(b^3*(b*c - a*d)^3) - (2*c^3*(b*c - 2*a*d)*Log[c + d*x])/(d^3*(b*c - a*d)^3)

Rule 88

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandI
ntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] &&
(IntegerQ[p] || (GtQ[m, 0] && GeQ[n, -1]))

Rubi steps

\begin {align*} \int \frac {x^4}{(a+b x)^2 (c+d x)^2} \, dx &=\int \left (\frac {1}{b^2 d^2}+\frac {a^4}{b^2 (b c-a d)^2 (a+b x)^2}+\frac {2 a^3 (-2 b c+a d)}{b^2 (b c-a d)^3 (a+b x)}+\frac {c^4}{d^2 (-b c+a d)^2 (c+d x)^2}+\frac {2 c^3 (b c-2 a d)}{d^2 (-b c+a d)^3 (c+d x)}\right ) \, dx\\ &=\frac {x}{b^2 d^2}-\frac {a^4}{b^3 (b c-a d)^2 (a+b x)}-\frac {c^4}{d^3 (b c-a d)^2 (c+d x)}-\frac {2 a^3 (2 b c-a d) \log (a+b x)}{b^3 (b c-a d)^3}-\frac {2 c^3 (b c-2 a d) \log (c+d x)}{d^3 (b c-a d)^3}\\ \end {align*}

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Mathematica [A]  time = 0.17, size = 123, normalized size = 0.99 \begin {gather*} -\frac {a^4}{b^3 (a+b x) (b c-a d)^2}+\frac {2 a^3 (a d-2 b c) \log (a+b x)}{b^3 (b c-a d)^3}-\frac {c^4}{d^3 (c+d x) (b c-a d)^2}+\frac {2 c^3 (b c-2 a d) \log (c+d x)}{d^3 (a d-b c)^3}+\frac {x}{b^2 d^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^4/((a + b*x)^2*(c + d*x)^2),x]

[Out]

x/(b^2*d^2) - a^4/(b^3*(b*c - a*d)^2*(a + b*x)) - c^4/(d^3*(b*c - a*d)^2*(c + d*x)) + (2*a^3*(-2*b*c + a*d)*Lo
g[a + b*x])/(b^3*(b*c - a*d)^3) + (2*c^3*(b*c - 2*a*d)*Log[c + d*x])/(d^3*(-(b*c) + a*d)^3)

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^4}{(a+b x)^2 (c+d x)^2} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[x^4/((a + b*x)^2*(c + d*x)^2),x]

[Out]

IntegrateAlgebraic[x^4/((a + b*x)^2*(c + d*x)^2), x]

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fricas [B]  time = 0.93, size = 537, normalized size = 4.33 \begin {gather*} -\frac {a b^{4} c^{5} - a^{2} b^{3} c^{4} d + a^{4} b c^{2} d^{3} - a^{5} c d^{4} - {\left (b^{5} c^{3} d^{2} - 3 \, a b^{4} c^{2} d^{3} + 3 \, a^{2} b^{3} c d^{4} - a^{3} b^{2} d^{5}\right )} x^{3} - {\left (b^{5} c^{4} d - 2 \, a b^{4} c^{3} d^{2} + 2 \, a^{3} b^{2} c d^{4} - a^{4} b d^{5}\right )} x^{2} + {\left (b^{5} c^{5} - 2 \, a b^{4} c^{4} d + 3 \, a^{2} b^{3} c^{3} d^{2} - 3 \, a^{3} b^{2} c^{2} d^{3} + 2 \, a^{4} b c d^{4} - a^{5} d^{5}\right )} x + 2 \, {\left (2 \, a^{4} b c^{2} d^{3} - a^{5} c d^{4} + {\left (2 \, a^{3} b^{2} c d^{4} - a^{4} b d^{5}\right )} x^{2} + {\left (2 \, a^{3} b^{2} c^{2} d^{3} + a^{4} b c d^{4} - a^{5} d^{5}\right )} x\right )} \log \left (b x + a\right ) + 2 \, {\left (a b^{4} c^{5} - 2 \, a^{2} b^{3} c^{4} d + {\left (b^{5} c^{4} d - 2 \, a b^{4} c^{3} d^{2}\right )} x^{2} + {\left (b^{5} c^{5} - a b^{4} c^{4} d - 2 \, a^{2} b^{3} c^{3} d^{2}\right )} x\right )} \log \left (d x + c\right )}{a b^{6} c^{4} d^{3} - 3 \, a^{2} b^{5} c^{3} d^{4} + 3 \, a^{3} b^{4} c^{2} d^{5} - a^{4} b^{3} c d^{6} + {\left (b^{7} c^{3} d^{4} - 3 \, a b^{6} c^{2} d^{5} + 3 \, a^{2} b^{5} c d^{6} - a^{3} b^{4} d^{7}\right )} x^{2} + {\left (b^{7} c^{4} d^{3} - 2 \, a b^{6} c^{3} d^{4} + 2 \, a^{3} b^{4} c d^{6} - a^{4} b^{3} d^{7}\right )} x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4/(b*x+a)^2/(d*x+c)^2,x, algorithm="fricas")

[Out]

-(a*b^4*c^5 - a^2*b^3*c^4*d + a^4*b*c^2*d^3 - a^5*c*d^4 - (b^5*c^3*d^2 - 3*a*b^4*c^2*d^3 + 3*a^2*b^3*c*d^4 - a
^3*b^2*d^5)*x^3 - (b^5*c^4*d - 2*a*b^4*c^3*d^2 + 2*a^3*b^2*c*d^4 - a^4*b*d^5)*x^2 + (b^5*c^5 - 2*a*b^4*c^4*d +
3*a^2*b^3*c^3*d^2 - 3*a^3*b^2*c^2*d^3 + 2*a^4*b*c*d^4 - a^5*d^5)*x + 2*(2*a^4*b*c^2*d^3 - a^5*c*d^4 + (2*a^3*
b^2*c*d^4 - a^4*b*d^5)*x^2 + (2*a^3*b^2*c^2*d^3 + a^4*b*c*d^4 - a^5*d^5)*x)*log(b*x + a) + 2*(a*b^4*c^5 - 2*a^
2*b^3*c^4*d + (b^5*c^4*d - 2*a*b^4*c^3*d^2)*x^2 + (b^5*c^5 - a*b^4*c^4*d - 2*a^2*b^3*c^3*d^2)*x)*log(d*x + c))
/(a*b^6*c^4*d^3 - 3*a^2*b^5*c^3*d^4 + 3*a^3*b^4*c^2*d^5 - a^4*b^3*c*d^6 + (b^7*c^3*d^4 - 3*a*b^6*c^2*d^5 + 3*a
^2*b^5*c*d^6 - a^3*b^4*d^7)*x^2 + (b^7*c^4*d^3 - 2*a*b^6*c^3*d^4 + 2*a^3*b^4*c*d^6 - a^4*b^3*d^7)*x)

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giac [B]  time = 0.93, size = 312, normalized size = 2.52 \begin {gather*} -\frac {a^{4} b^{3}}{{\left (b^{8} c^{2} - 2 \, a b^{7} c d + a^{2} b^{6} d^{2}\right )} {\left (b x + a\right )}} - \frac {2 \, {\left (b^{2} c^{4} - 2 \, a b c^{3} d\right )} \log \left ({\left | \frac {b c}{b x + a} - \frac {a d}{b x + a} + d \right |}\right )}{b^{4} c^{3} d^{3} - 3 \, a b^{3} c^{2} d^{4} + 3 \, a^{2} b^{2} c d^{5} - a^{3} b d^{6}} + \frac {2 \, {\left (b c + a d\right )} \log \left (\frac {{\left | b x + a \right |}}{{\left (b x + a\right )}^{2} {\left | b \right |}}\right )}{b^{3} d^{3}} + \frac {{\left (b^{2} c^{2} d - 2 \, a b c d^{2} + a^{2} d^{3} + \frac {2 \, b^{5} c^{4} - 4 \, a b^{4} c^{3} d + 6 \, a^{2} b^{3} c^{2} d^{2} - 4 \, a^{3} b^{2} c d^{3} + a^{4} b d^{4}}{{\left (b c - a d\right )} {\left (b x + a\right )} b}\right )} {\left (b x + a\right )}}{{\left (b c - a d\right )}^{2} b^{3} {\left (\frac {b c}{b x + a} - \frac {a d}{b x + a} + d\right )} d^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4/(b*x+a)^2/(d*x+c)^2,x, algorithm="giac")

[Out]

-a^4*b^3/((b^8*c^2 - 2*a*b^7*c*d + a^2*b^6*d^2)*(b*x + a)) - 2*(b^2*c^4 - 2*a*b*c^3*d)*log(abs(b*c/(b*x + a) -
a*d/(b*x + a) + d))/(b^4*c^3*d^3 - 3*a*b^3*c^2*d^4 + 3*a^2*b^2*c*d^5 - a^3*b*d^6) + 2*(b*c + a*d)*log(abs(b*x
+ a)/((b*x + a)^2*abs(b)))/(b^3*d^3) + (b^2*c^2*d - 2*a*b*c*d^2 + a^2*d^3 + (2*b^5*c^4 - 4*a*b^4*c^3*d + 6*a^
2*b^3*c^2*d^2 - 4*a^3*b^2*c*d^3 + a^4*b*d^4)/((b*c - a*d)*(b*x + a)*b))*(b*x + a)/((b*c - a*d)^2*b^3*(b*c/(b*x
+ a) - a*d/(b*x + a) + d)*d^2)

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maple [A]  time = 0.02, size = 160, normalized size = 1.29 \begin {gather*} -\frac {2 a^{4} d \ln \left (b x +a \right )}{\left (a d -b c \right )^{3} b^{3}}+\frac {4 a^{3} c \ln \left (b x +a \right )}{\left (a d -b c \right )^{3} b^{2}}-\frac {4 a \,c^{3} \ln \left (d x +c \right )}{\left (a d -b c \right )^{3} d^{2}}+\frac {2 b \,c^{4} \ln \left (d x +c \right )}{\left (a d -b c \right )^{3} d^{3}}-\frac {a^{4}}{\left (a d -b c \right )^{2} \left (b x +a \right ) b^{3}}-\frac {c^{4}}{\left (a d -b c \right )^{2} \left (d x +c \right ) d^{3}}+\frac {x}{b^{2} d^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^4/(b*x+a)^2/(d*x+c)^2,x)

[Out]

x/b^2/d^2-1/d^3*c^4/(a*d-b*c)^2/(d*x+c)-4/d^2*c^3/(a*d-b*c)^3*ln(d*x+c)*a+2/d^3*c^4/(a*d-b*c)^3*ln(d*x+c)*b-1/
b^3*a^4/(a*d-b*c)^2/(b*x+a)-2/b^3*a^4/(a*d-b*c)^3*ln(b*x+a)*d+4/b^2*a^3/(a*d-b*c)^3*ln(b*x+a)*c

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maxima [B]  time = 1.17, size = 295, normalized size = 2.38 \begin {gather*} -\frac {2 \, {\left (2 \, a^{3} b c - a^{4} d\right )} \log \left (b x + a\right )}{b^{6} c^{3} - 3 \, a b^{5} c^{2} d + 3 \, a^{2} b^{4} c d^{2} - a^{3} b^{3} d^{3}} - \frac {2 \, {\left (b c^{4} - 2 \, a c^{3} d\right )} \log \left (d x + c\right )}{b^{3} c^{3} d^{3} - 3 \, a b^{2} c^{2} d^{4} + 3 \, a^{2} b c d^{5} - a^{3} d^{6}} - \frac {a b^{3} c^{4} + a^{4} c d^{3} + {\left (b^{4} c^{4} + a^{4} d^{4}\right )} x}{a b^{5} c^{3} d^{3} - 2 \, a^{2} b^{4} c^{2} d^{4} + a^{3} b^{3} c d^{5} + {\left (b^{6} c^{2} d^{4} - 2 \, a b^{5} c d^{5} + a^{2} b^{4} d^{6}\right )} x^{2} + {\left (b^{6} c^{3} d^{3} - a b^{5} c^{2} d^{4} - a^{2} b^{4} c d^{5} + a^{3} b^{3} d^{6}\right )} x} + \frac {x}{b^{2} d^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4/(b*x+a)^2/(d*x+c)^2,x, algorithm="maxima")

[Out]

-2*(2*a^3*b*c - a^4*d)*log(b*x + a)/(b^6*c^3 - 3*a*b^5*c^2*d + 3*a^2*b^4*c*d^2 - a^3*b^3*d^3) - 2*(b*c^4 - 2*a
*c^3*d)*log(d*x + c)/(b^3*c^3*d^3 - 3*a*b^2*c^2*d^4 + 3*a^2*b*c*d^5 - a^3*d^6) - (a*b^3*c^4 + a^4*c*d^3 + (b^4
*c^4 + a^4*d^4)*x)/(a*b^5*c^3*d^3 - 2*a^2*b^4*c^2*d^4 + a^3*b^3*c*d^5 + (b^6*c^2*d^4 - 2*a*b^5*c*d^5 + a^2*b^4
*d^6)*x^2 + (b^6*c^3*d^3 - a*b^5*c^2*d^4 - a^2*b^4*c*d^5 + a^3*b^3*d^6)*x) + x/(b^2*d^2)

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mupad [B]  time = 0.60, size = 274, normalized size = 2.21 \begin {gather*} \frac {x}{b^2\,d^2}-\frac {\frac {x\,\left (a^4\,d^4+b^4\,c^4\right )}{b\,d\,\left (a^2\,d^2-2\,a\,b\,c\,d+b^2\,c^2\right )}+\frac {a\,c\,\left (a^3\,d^3+b^3\,c^3\right )}{b\,d\,\left (a^2\,d^2-2\,a\,b\,c\,d+b^2\,c^2\right )}}{x\,\left (c\,b^3\,d^2+a\,b^2\,d^3\right )+b^3\,d^3\,x^2+a\,b^2\,c\,d^2}+\frac {\ln \left (a+b\,x\right )\,\left (2\,a^4\,d-4\,a^3\,b\,c\right )}{-a^3\,b^3\,d^3+3\,a^2\,b^4\,c\,d^2-3\,a\,b^5\,c^2\,d+b^6\,c^3}+\frac {\ln \left (c+d\,x\right )\,\left (2\,b\,c^4-4\,a\,c^3\,d\right )}{a^3\,d^6-3\,a^2\,b\,c\,d^5+3\,a\,b^2\,c^2\,d^4-b^3\,c^3\,d^3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^4/((a + b*x)^2*(c + d*x)^2),x)

[Out]

x/(b^2*d^2) - ((x*(a^4*d^4 + b^4*c^4))/(b*d*(a^2*d^2 + b^2*c^2 - 2*a*b*c*d)) + (a*c*(a^3*d^3 + b^3*c^3))/(b*d*
(a^2*d^2 + b^2*c^2 - 2*a*b*c*d)))/(x*(a*b^2*d^3 + b^3*c*d^2) + b^3*d^3*x^2 + a*b^2*c*d^2) + (log(a + b*x)*(2*a
^4*d - 4*a^3*b*c))/(b^6*c^3 - a^3*b^3*d^3 + 3*a^2*b^4*c*d^2 - 3*a*b^5*c^2*d) + (log(c + d*x)*(2*b*c^4 - 4*a*c^
3*d))/(a^3*d^6 - b^3*c^3*d^3 + 3*a*b^2*c^2*d^4 - 3*a^2*b*c*d^5)

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sympy [B]  time = 7.89, size = 695, normalized size = 5.60 \begin {gather*} - \frac {2 a^{3} \left (a d - 2 b c\right ) \log {\left (x + \frac {\frac {2 a^{7} d^{6} \left (a d - 2 b c\right )}{b \left (a d - b c\right )^{3}} - \frac {8 a^{6} c d^{5} \left (a d - 2 b c\right )}{\left (a d - b c\right )^{3}} + \frac {12 a^{5} b c^{2} d^{4} \left (a d - 2 b c\right )}{\left (a d - b c\right )^{3}} - \frac {8 a^{4} b^{2} c^{3} d^{3} \left (a d - 2 b c\right )}{\left (a d - b c\right )^{3}} + 2 a^{4} c d^{3} + \frac {2 a^{3} b^{3} c^{4} d^{2} \left (a d - 2 b c\right )}{\left (a d - b c\right )^{3}} - 4 a^{3} b c^{2} d^{2} - 4 a^{2} b^{2} c^{3} d + 2 a b^{3} c^{4}}{2 a^{4} d^{4} - 4 a^{3} b c d^{3} - 4 a b^{3} c^{3} d + 2 b^{4} c^{4}} \right )}}{b^{3} \left (a d - b c\right )^{3}} - \frac {2 c^{3} \left (2 a d - b c\right ) \log {\left (x + \frac {\frac {2 a^{4} b^{2} c^{3} d^{3} \left (2 a d - b c\right )}{\left (a d - b c\right )^{3}} + 2 a^{4} c d^{3} - \frac {8 a^{3} b^{3} c^{4} d^{2} \left (2 a d - b c\right )}{\left (a d - b c\right )^{3}} - 4 a^{3} b c^{2} d^{2} + \frac {12 a^{2} b^{4} c^{5} d \left (2 a d - b c\right )}{\left (a d - b c\right )^{3}} - 4 a^{2} b^{2} c^{3} d - \frac {8 a b^{5} c^{6} \left (2 a d - b c\right )}{\left (a d - b c\right )^{3}} + 2 a b^{3} c^{4} + \frac {2 b^{6} c^{7} \left (2 a d - b c\right )}{d \left (a d - b c\right )^{3}}}{2 a^{4} d^{4} - 4 a^{3} b c d^{3} - 4 a b^{3} c^{3} d + 2 b^{4} c^{4}} \right )}}{d^{3} \left (a d - b c\right )^{3}} + \frac {- a^{4} c d^{3} - a b^{3} c^{4} + x \left (- a^{4} d^{4} - b^{4} c^{4}\right )}{a^{3} b^{3} c d^{5} - 2 a^{2} b^{4} c^{2} d^{4} + a b^{5} c^{3} d^{3} + x^{2} \left (a^{2} b^{4} d^{6} - 2 a b^{5} c d^{5} + b^{6} c^{2} d^{4}\right ) + x \left (a^{3} b^{3} d^{6} - a^{2} b^{4} c d^{5} - a b^{5} c^{2} d^{4} + b^{6} c^{3} d^{3}\right )} + \frac {x}{b^{2} d^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**4/(b*x+a)**2/(d*x+c)**2,x)

[Out]

-2*a**3*(a*d - 2*b*c)*log(x + (2*a**7*d**6*(a*d - 2*b*c)/(b*(a*d - b*c)**3) - 8*a**6*c*d**5*(a*d - 2*b*c)/(a*d
- b*c)**3 + 12*a**5*b*c**2*d**4*(a*d - 2*b*c)/(a*d - b*c)**3 - 8*a**4*b**2*c**3*d**3*(a*d - 2*b*c)/(a*d - b*c
)**3 + 2*a**4*c*d**3 + 2*a**3*b**3*c**4*d**2*(a*d - 2*b*c)/(a*d - b*c)**3 - 4*a**3*b*c**2*d**2 - 4*a**2*b**2*c
**3*d + 2*a*b**3*c**4)/(2*a**4*d**4 - 4*a**3*b*c*d**3 - 4*a*b**3*c**3*d + 2*b**4*c**4))/(b**3*(a*d - b*c)**3)
- 2*c**3*(2*a*d - b*c)*log(x + (2*a**4*b**2*c**3*d**3*(2*a*d - b*c)/(a*d - b*c)**3 + 2*a**4*c*d**3 - 8*a**3*b*
*3*c**4*d**2*(2*a*d - b*c)/(a*d - b*c)**3 - 4*a**3*b*c**2*d**2 + 12*a**2*b**4*c**5*d*(2*a*d - b*c)/(a*d - b*c)
**3 - 4*a**2*b**2*c**3*d - 8*a*b**5*c**6*(2*a*d - b*c)/(a*d - b*c)**3 + 2*a*b**3*c**4 + 2*b**6*c**7*(2*a*d - b
*c)/(d*(a*d - b*c)**3))/(2*a**4*d**4 - 4*a**3*b*c*d**3 - 4*a*b**3*c**3*d + 2*b**4*c**4))/(d**3*(a*d - b*c)**3)
+ (-a**4*c*d**3 - a*b**3*c**4 + x*(-a**4*d**4 - b**4*c**4))/(a**3*b**3*c*d**5 - 2*a**2*b**4*c**2*d**4 + a*b**
5*c**3*d**3 + x**2*(a**2*b**4*d**6 - 2*a*b**5*c*d**5 + b**6*c**2*d**4) + x*(a**3*b**3*d**6 - a**2*b**4*c*d**5
- a*b**5*c**2*d**4 + b**6*c**3*d**3)) + x/(b**2*d**2)

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